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(D) Given:Focal length of objective,$f_0 = 20\,m = 2000\,cm$.Focal length of eyepiece,$f_e = 2\,cm$.For normal adjustment:$1$. The distance between th

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$(a), (b)$ and $(d)$

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(D) Given:Focal length of objective,$f_0 = 20\,m = 2000\,cm$.Focal length of eyepiece,$f_e = 2\,cm$.For normal adjustment:$1$. The distance between the objective and the eyepiece is $L = f_0 + f_e = 2000\,cm + 2\,cm = 2002\,cm = 20.02\,m$. Thus,statement $(a)$ is correct.$2$. The magnifying power (magnification) is $M = \frac{f_0}{f_e} = \frac{2000}{2} = 1000$. Thus,statement $(b)$ is correct.$3$. In an astronomical telescope,the final image formed is inverted and magnified relative to the object. Thus,statement $(c)$ is incorrect.$4$. The aperture of the eyepiece is kept smaller than that of the objective to ensure that all light rays collected by the objective enter the eye. Thus,statement $(d)$ is correct.Therefore,the correct statements are $(a), (b),$ and $(d)$.

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