An aromatic compound A of formula C_7H_6Cl_2 | vedclass

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(A) Compound $A$ is $p-$chlorobenzyl chloride $(Cl-C_6H_4-CH_2Cl)$. It reacts with alcoholic $AgNO_3$ to form $AgCl$ due to the presence of a reactive

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$p-$chlorobenzyl chloride

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(A) Compound $A$ is $p-$chlorobenzyl chloride $(Cl-C_6H_4-CH_2Cl)$. It reacts with alcoholic $AgNO_3$ to form $AgCl$ due to the presence of a reactive benzylic chloride group. Treatment with $NaOH$ results in the nucleophilic substitution of the benzylic chlorine to form $p-$chlorobenzyl alcohol $(Cl-C_6H_4-CH_2OH)$,which corresponds to the formula $C_7H_7OCl$. Oxidation of the side chain of $A$ yields $p-$chlorobenzoic acid. Due to the symmetry of the $p-$substituted benzene ring,$p-$chlorobenzoic acid provides only one mononitro derivative upon nitration.

Column-$I$ (Reactants)	Column-$II$ (Name)
$A$. $R-X + NaI \xrightarrow{\text{dry acetone}} R-I + NaX$	$i$. Electrophilic addition
$B$. $H_3C-Br + AgF \to H_3C-F + AgBr$	$ii$. Finkelstein reaction
$C$. $H_3C-CH_3 + Cl_2 \xrightarrow{hv} H_3C-CH_2Cl + HCl$	$iii$. Swarts reaction
$D$. $CH_2=CH_2 + Br_2 \to BrCH_2-CH_2Br$	$iv$. Free radical substitution

An aromatic compound $A$ of formula $C_7H_6Cl_2$ gives $AgCl$ on boiling with alcoholic $AgNO_3$ solution,and yields $C_7H_7OCl$ on treatment with sodium hydroxide. $A$ on oxidation gives a monochlorobenzoic acid which affords only one mononitro derivative. The compound $A$ is :

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