An aqueous solution of sodium nitrite on boil | vedclass

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Question

(B) The reaction of $\alpha$-chlorosodium propionate $(CH_3CHClCOONa)$ with aqueous sodium nitrite $(NaNO_2)$ involves the displacement of the chlorin

Vedclass · Accepted Answer

Nitroethane

Vedclass · Answer

(B) The reaction of $\alpha$-chlorosodium propionate $(CH_3CHClCOONa)$ with aqueous sodium nitrite $(NaNO_2)$ involves the displacement of the chlorine atom by the nitrite group,followed by decarboxylation upon boiling. The reaction proceeds as follows: $CH_3CHClCOONa + NaNO_2 \rightarrow CH_3CH(NO_2)COONa + NaCl$ Upon boiling,the intermediate undergoes decarboxylation: $CH_3CH(NO_2)COONa \xrightarrow{\Delta} CH_3CH_2NO_2 + CO_2 + NaCl$ Thus,the final product is nitroethane.

Column $I$	Column $II$
$(A)$ $CH_3CH_2CH_2CH_2NH_2$	$(i)$ Secondary amine
$(B)$ $(CH_3CH_2)_2NH$	$(ii)$ Tertiary amine
$(C)$ $(CH_3)_3N$	$(iii)$ Aromatic amine
$(D)$ $C_6H_5NH_2$	$(iv)$ Quaternary ammonium salt
	$(v)$ Primary amine

An aqueous solution of sodium nitrite on boiling with $\alpha$-chlorosodium propionate gives:

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Match the following:

Column $I$ Column $II$

$(A)$ $CH_3CH_2CH_2CH_2NH_2$ $(i)$ Secondary amine

$(B)$ $(CH_3CH_2)_2NH$ $(ii)$ Tertiary amine

$(C)$ $(CH_3)_3N$ $(iii)$ Aromatic amine

$(D)$ $C_6H_5NH_2$ $(iv)$ Quaternary ammonium salt

$(v)$ Primary amine

The correct match is:

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