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(B) The solution contains both $A$ and $B$ and exhibits optical activity. If $A$ and $B$ were enantiomers present in equal amounts,the mixture would b

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$A$ and $B$ are enantiomers

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(B) The solution contains both $A$ and $B$ and exhibits optical activity. If $A$ and $B$ were enantiomers present in equal amounts,the mixture would be a racemic mixture,which is optically inactive. Therefore,if the mixture is optically active,$A$ and $B$ cannot be enantiomers present in equal amounts. Option $A$ is possible if $A$ is chiral and $B$ is a meso compound (which is achiral),provided the mixture is not a racemic mixture. Option $B$ is incorrect because if $A$ and $B$ are enantiomers,they must be present in unequal amounts to show optical activity,but the statement implies a general impossibility. However,the most direct contradiction to the mixture showing optical activity is the implication that $A$ and $B$ are enantiomers in a context where they would cancel each other out.

An aqueous solution containing compounds $A$ and $B$ shows optical activity. $A$ and $B$ are stereoisomers. Which of the following possibilities cannot be correct?

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