An ammeter gives full scale deflection when a | vedclass

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(D) The formula for the shunt resistance $S$ required to convert a galvanometer of resistance $G$ into an ammeter of range $I$ is given by $S = \frac{

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$9: 1$

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(D) The formula for the shunt resistance $S$ required to convert a galvanometer of resistance $G$ into an ammeter of range $I$ is given by $S = \frac{G I_g}{I - I_g}$,where $I_g$ is the full-scale deflection current.Rearranging this formula to find the ratio of the galvanometer resistance $G$ to the shunt resistance $S$,we get $\frac{G}{S} = \frac{I - I_g}{I_g}$.Given values are $I = 10 \ A$ and $I_g = 1.0 \ A$.Substituting these values into the ratio expression: $\frac{G}{S} = \frac{10 - 1}{1} = \frac{9}{1}$.Thus,the ratio of its resistance to the shunt resistance is $9:1$.

An ammeter gives full scale deflection when a current of $1.0 \ A$ is passed through it. To convert it into a $10 \ A$ range ammeter,the ratio of its resistance $(G)$ to the shunt resistance $(S)$ will be:

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