An alternating electric field,of frequency $f$,is applied across the dees (radius $\approx R$) of a cyclotron that is being used to accelerate protons (mass $\approx m$). The operating magnetic field $(B)$ used in the cyclotron and the kinetic energy $(K)$ of the proton beam,produced by it,are given by:

  • A
    $B = \frac{mf}{e}$,$K = 2m\pi^2f^2R^2$
  • B
    $B = \frac{2\pi mf}{e}$,$K = \pi m^2f^2R^2$
  • C
    $B = \frac{2\pi mf}{e}$,$K = 2m\pi^2f^2R^2$
  • D
    $B = \frac{mf}{e}$,$K = \pi m^2f^2R^2$

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Write the resonance condition for a cyclotron.

If the maximum value of accelerating potential provided by a radio frequency oscillator is $12 \, kV$,the number of revolutions made by a proton in a cyclotron to achieve one-sixth of the speed of light is ....... .
$[m_p = 1.67 \times 10^{-27} \, kg, e = 1.6 \times 10^{-19} \, C, c = 3 \times 10^8 \, m/s]$

$A$ proton is accelerating in a cyclotron where the applied magnetic field is $2 \,T$. If the potential gap is effectively $100 \,kV$, then how many revolutions does the proton have to make between the "dees" to acquire a kinetic energy of $20 \,MeV$?

Assertion : Cyclotron is a device which is used to accelerate the positive ion.
Reason : Cyclotron frequency depends upon the velocity.

The oscillator frequency of a cyclotron is $10 \,MHz$. What should be the operating magnetic field for accelerating protons (in $,T$)? (Given: mass of proton $m = 1.67 \times 10^{-27} \,kg$,charge of proton $q = 1.6 \times 10^{-19} \,C$)

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