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(C) The given equation for alternating current is $I = I_0 \sin(\omega t + \phi)$,where $I_0 = 20 \ A$ and $\omega = 100 \pi \ rad/s$.The root mean sq

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$10 \sqrt{2} \ A$ and $50 \ Hz$

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(C) The given equation for alternating current is $I = I_0 \sin(\omega t + \phi)$,where $I_0 = 20 \ A$ and $\omega = 100 \pi \ rad/s$.The root mean square (r.m.s.) value of the current is given by $I_{rms} = \frac{I_0}{\sqrt{2}}$.Substituting the value of $I_0$: $I_{rms} = \frac{20}{\sqrt{2}} = 10 \sqrt{2} \ A$.The angular frequency is $\omega = 2 \pi f = 100 \pi$.Solving for frequency $f$: $f = \frac{100 \pi}{2 \pi} = 50 \ Hz$.Therefore,the r.m.s. value is $10 \sqrt{2} \ A$ and the frequency is $50 \ Hz$.

An alternating current in a circuit is given by $I = 20 \sin (100 \pi t + 0.05 \pi) \ A$. The r.m.s. value and the frequency of the current respectively are:

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