An alpha particle $\left({ }^{4} He\right)$ has a mass of $4.00300 \ amu$. $A$ proton has a mass of $1.00783 \ amu$ and a neutron has a mass of $1.00867 \ amu$. The binding energy of an alpha particle estimated from these data is closest to: (in $MeV$)

  • A
    $27.9$
  • B
    $22.3$
  • C
    $35.0$
  • D
    $20.4$

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$A$ given coin has a mass of $3.0\; g$. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity, assume that the coin is entirely made of $_{29}^{63} Cu$ atoms (of mass $62.92960\; u$).

The radionuclide $^{11}_{6}C$ decays by $\beta^+$ emission. Given that $m(^{11}_{6}C) = 11.011434 \ u$,$m(^{11}_{5}B) = 11.009305 \ u$,$m_e = 0.000548 \ u$,and $1 \ u = 931.5 \ MeV/c^2$. The $Q$-value of this decay process is:

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The mass of a ${}_{3}^{7}Li$ nucleus is $0.042 \, u$ less than the sum of the masses of all its nucleons. The binding energy per nucleon of ${}_{3}^{7}Li$ nucleus is nearly...........$MeV$.

The rest mass of the deuteron,${}_1^2H$,is equivalent to an energy of $1876 \, MeV$. The rest mass of a proton is equivalent to $939 \, MeV$ and that of a neutron is $940 \, MeV$. $A$ deuteron may disintegrate into a proton and a neutron if it:

The plot of binding energy per nucleon against the mass number for stable nuclei is shown in the figure. Which curve is correct?

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