An alkyl bromide (X) reacts with Na in the pr | vedclass

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(D) The reaction of an alkyl bromide with $Na$ in dry ether is the Wurtz reaction,which doubles the alkyl chain.$4, 5-$diethyloctane has the structure

Vedclass · Accepted Answer

$CH_3(CH_2)_2CH(Br)CH_2CH_3$

Vedclass · Answer

(D) The reaction of an alkyl bromide with $Na$ in dry ether is the Wurtz reaction,which doubles the alkyl chain.$4, 5-$diethyloctane has the structure: $CH_3-CH_2-CH_2-CH(C_2H_5)-CH(C_2H_5)-CH_2-CH_2-CH_3$.This molecule is symmetric. Splitting it at the bond between $C_4$ and $C_5$ gives two identical fragments: $CH_3-CH_2-CH_2-CH(C_2H_5)-$.This fragment corresponds to $1-$bromopentane derivative,specifically $3-$bromopentane is not correct,but $CH_3-CH_2-CH_2-CH(Br)-CH_2-CH_3$ is $3-$bromohexane. Let us re-evaluate the structure.$4, 5-$diethyloctane is $CH_3CH_2CH_2CH(CH_2CH_3)CH(CH_2CH_3)CH_2CH_2CH_3$.Splitting at the center gives $CH_3CH_2CH_2CH(Br)CH_2CH_3$,which is $3-$bromohexane.Comparing this with the options,option $(D)$ is $CH_3(CH_2)_2CH(Br)CH_2CH_3$,which is $3-$bromohexane.

An alkyl bromide $(X)$ reacts with $Na$ in the presence of dry ether to form $4, 5-$diethyloctane. Compound $(X)$ is

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