An alkene of molecular formula C_9H_{18} on o | vedclass

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(A) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond and the addition of oxygen atoms to each carbon atom to form carbonyl compo

Vedclass · Accepted Answer

$2,2,4$-trimethylhex$-3$-ene

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(A) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond and the addition of oxygen atoms to each carbon atom to form carbonyl compounds.Given products are $2,2$-dimethylpropanal $(CH_3)_3C-CHO$ and butan$-2$-one $(CH_3-CO-CH_2CH_3)$.To find the original alkene,we join the carbonyl carbons by removing the oxygen atoms and forming a double bond between them:$(CH_3)_3C-CH=O + O=C(CH_3)CH_2CH_3 \rightarrow (CH_3)_3C-CH=C(CH_3)CH_2CH_3$.The resulting structure is $2,2,4$-trimethylhex$-3$-ene.

An alkene of molecular formula $C_9H_{18}$ on ozonolysis gives $2,2$-dimethylpropanal and butan$-2$-one. The alkene is:

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