An alkene X on ozonolysis gives a mixture of | vedclass

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(A) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds.To find the original alkene,we join the two carb

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$2-Methylpropene$

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(A) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds.To find the original alkene,we join the two carbonyl products by removing the oxygen atoms and forming a double bond between the carbon atoms.The products are $Propan-2-one$ $(CH_3-CO-CH_3)$ and $methanal$ $(H-CHO)$.Joining these: $(CH_3)_2C=O + O=CH_2 \rightarrow (CH_3)_2C=CH_2$.The resulting alkene is $2-Methylpropene$.

An alkene $X$ on ozonolysis gives a mixture of $Propan-2-one$ and $methanal$. What is $X$?

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