An alkali metal hydride (NaH) reacts with dib | vedclass

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(D) The reaction between sodium hydride $(NaH)$ and diborane $(B_{2}H_{6})$ occurs in an ether solvent,typically diethyl ether,$(C_{2}H_{5})_{2}O$,to

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$(C_{2}H_{5})_{2}O$ and $NaBH_{4}$

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(D) The reaction between sodium hydride $(NaH)$ and diborane $(B_{2}H_{6})$ occurs in an ether solvent,typically diethyl ether,$(C_{2}H_{5})_{2}O$,to produce sodium borohydride $(NaBH_{4})$.The chemical equation is: $2NaH + B_{2}H_{6} \xrightarrow{(C_{2}H_{5})_{2}O} 2NaBH_{4}$.Here,'$A$' is $(C_{2}H_{5})_{2}O$ and '$B$' is $NaBH_{4}$,which is a well-known reducing agent.

An alkali metal hydride $(NaH)$ reacts with diborane in '$A$' to give a tetrahedral compound '$B$' which is extensively used as a reducing agent in organic synthesis. The compounds '$A$' and '$B$' respectively are

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