An a.c. source of voltage V and frequency 50, | vedclass

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(D) The inductive reactance is given by $X_L = \omega L = 2\pi f L$.For $f_1 = 50\,Hz$ and $L = 2\,H$,the reactance is $X_{L1} = 2\pi 	imes 50 	imes

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$I/8$ and lagging by $90^o$ from $V$

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(D) The inductive reactance is given by $X_L = \omega L = 2\pi f L$.For $f_1 = 50\,Hz$ and $L = 2\,H$,the reactance is $X_{L1} = 2\pi 	imes 50 	imes 2 = 200\pi\,\Omega$.The initial current is $I = V / X_{L1} = V / (200\pi)$.When the frequency is changed to $f_2 = 400\,Hz$,the new inductive reactance is $X_{L2} = 2\pi 	imes 400 	imes 2 = 1600\pi\,\Omega$.The new current $I'$ is $I' = V / X_{L2} = V / (1600\pi)$.Comparing the two currents: $I' = (V / 200\pi) / 8 = I / 8$.In a purely inductive circuit,the current lags the voltage by $90^o$.

An $a.c.$ source of voltage $V$ and frequency $50\,Hz$ is connected to an inductor of $2\,H$ and negligible resistance. $A$ current of $r.m.s.$ value $I$ flows in the coil. When the frequency of the voltage is changed to $400\,Hz$ keeping the magnitude of $V$ the same,the current is now

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