An $L-C$ resonant circuit contains a $400 \ pF$ capacitor and an inductor of $400 \ \mu H$. It is coupled to an antenna. The wavelength of the radiated electromagnetic wave is:

The frequency of the output signal of an $LC$ oscillator circuit is $F \ Hz$ with a capacitance of $0.1 \ \mu F$. If the value of the capacitor is increased to $0.2 \ \mu F$,then the frequency of the output signal will be

In the given circuit, the resonant frequency is (in $ Hz$)

In an $LC$ circuit,the angular frequency at resonance is $\omega$. What will be the new angular frequency when the inductor's inductance is made two times and the capacitor's capacitance is made four times?

$A$ capacitor of capacitance $100 \ \mu F$ is charged to a potential of $12 \ V$ and connected to a $6.4 \ mH$ inductor to produce oscillations. The maximum current in the circuit would be: (in $A$)

If $L = 1.00 \, mH$ and $C = 1.00 \, nF$,find the resonant frequency in $rad/s$.