An $LC$ series resonant circuit produces a resonant frequency $f$. If $L$ is tripled and $C$ is increased by $3C$ (making the new capacitance $4C$),the new resonant frequency will be:

To increase the resonant frequency in a series $LCR$ circuit,

$A$ $110 \; V, 50 \; Hz, AC$ source is connected in the circuit (as shown in figure). The current through the resistance $55 \; \Omega$,at resonance in the circuit,will be $\dots \; A$.

$A$ series $LCR$ circuit is connected across a source of alternating emf of changing frequency and resonates at frequency $f_0$. Keeping capacitance constant,if the inductance $(L)$ is increased by $\sqrt{3}$ times and resistance is increased $(R)$ by $1.4$ times,the resonant frequency now is

In an $L-C-R$ circuit,the capacitance is changed from $C$ to $2C$. For the resonant frequency to remain unchanged,the inductance should be changed from $L$ to:

An inductance of $2 \text{ mH}$,a capacitor of $20 \mu\text{F}$,and a resistance of $50 \Omega$ are connected in series to an $A.C.$ source. The reactance of the inductor and the capacitor are the same. The reactance of either of them will be: (in $Omega$)