An X-ray tube is operated at 1.24 million vol | vedclass

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(A) The shortest wavelength (cut-off wavelength) of $X$-rays produced in an $X$-ray tube is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$.Giv

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$10^{-3}$

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(A) The shortest wavelength (cut-off wavelength) of $X$-rays produced in an $X$-ray tube is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$.Given that the accelerating potential $V = 1.24 	imes 10^{6} \, V$,we can use the simplified relation: $\lambda_{\min} \approx \frac{1240}{V 	ext{ (in kV)}} \, nm$.Here,$V = 1.24 	imes 10^{6} \, V = 1240 	imes 10^{3} \, kV$.Substituting the values: $\lambda_{\min} = \frac{1240}{1.24 	imes 10^{6}} \, nm = 10^{-3} \, nm$.

An $X$-ray tube is operated at $1.24$ million volts. The shortest wavelength of the produced photon will be ..... $nm$.

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