Among the isoelectronic ions (O^{2-}, N^{3-}, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For isoelectronic species,the ionic radius decreases as the nuclear charge (number of protons) increases because the electrons are more strongly a

Vedclass · Accepted Answer

$Mg^{2+}, N^{3-}$

Vedclass · Answer

(A) For isoelectronic species,the ionic radius decreases as the nuclear charge (number of protons) increases because the electrons are more strongly attracted to the nucleus.						$Species$			$N^{3-}, O^{2-}, Na^{+}, Mg^{2+}$							$Number$ of electrons			$10, 10, 10, 10$							$Number$ of protons			$7, 8, 11, 12$			As the number of protons increases,the effective nuclear charge increases,leading to a smaller ionic radius.The order of ionic radius is: $Mg^{2+} Thus,$Mg^{2+}$ has the least ionic radius and $N^{3-}$ has the highest ionic radius.

Among the isoelectronic ions $(O^{2-}, N^{3-}, Mg^{2+}, Na^{+})$,the ions with the least and the highest ionic radius are,respectively

Similar Questions

The correct order of the atomic radii of $C, Cs, Al$ and $S$ is

Of the following,the ion with the smallest ionic radius is

Which of the following has the largest ionic radius?

The unit representing atomic radii and ionic radii is

Increasing order of ionic size for the ions,$F^{-}$,$O^{2-}$,$Na^{+}$,$Al^{3+}$ is :-

Vedclass Test Series

Exam Paper Generator

Online Exam Module