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(D) species is aromatic if it follows $H$ückel's rule,which states it must be planar,cyclic,fully conjugated,and contain $(4n+2)$ $\pi$-electrons,wher

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$I, II$ and $IV$

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(D) species is aromatic if it follows $H$ückel's rule,which states it must be planar,cyclic,fully conjugated,and contain $(4n+2)$ $\pi$-electrons,where $n = 0, 1, 2, \dots$$I$ (Benzene): Planar,cyclic,fully conjugated,$6$ $\pi$-electrons $(n=1)$. It is aromatic.$II$ (Naphthalene): Planar,cyclic,fully conjugated,$10$ $\pi$-electrons $(n=2)$. It is aromatic.$III$ (Cyclopentadiene): Not fully conjugated because of the $sp^3$ hybridized carbon. It is non-aromatic.$IV$ (Cyclopentadienyl anion): Planar,cyclic,fully conjugated,$6$ $\pi$-electrons $(n=1)$. It is aromatic.$V$ (Cyclooctatetraene): It has $8$ $\pi$-electrons ($4n$ system,$n=2$) and is non-planar (tub-shaped). It is non-aromatic.Thus,the aromatic species are $I, II$ and $IV$.

Among the following,the set which represents aromatic species is:

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