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(A) According to the $Hardy-Schulze$ law,the coagulating power of an ion depends on the magnitude of the charge carried by the ion.$Fe(OH)_{3}$ sol is

Vedclass · Accepted Answer

$PO_{4}^{3-}$

Vedclass · Answer

(A) According to the $Hardy-Schulze$ law,the coagulating power of an ion depends on the magnitude of the charge carried by the ion.$Fe(OH)_{3}$ sol is a positively charged sol.Therefore,the ion with the highest negative charge will be most effective for its flocculation.Comparing the charges of the given ions:$PO_{4}^{3-}$ has a charge of $-3$.$SO_{4}^{2-}$ has a charge of $-2$.$SO_{3}^{2-}$ has a charge of $-2$.$NO_{3}^{-}$ has a charge of $-1$.Since $PO_{4}^{3-}$ carries the highest negative charge,it is the most effective ion for the flocculation of $Fe(OH)_{3}$ sol.

Column $I$	Column $II$
$A$. Dialysis	$a$. Cleansing action of soap
$B$. Peptization	$b$. Coagulation
$C$. Emulsification	$c$. Colloidal solution preparation
$D$. Electrophoresis	$d$. Purification of colloidal solution

Among the following,the ion which will be more effective for flocculation of $Fe(OH)_{3}$ sol is:

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Match column $I$ (process) with column $II$ (application).
Column $I$ Column $II$
$A$. Dialysis $a$. Cleansing action of soap
$B$. Peptization $b$. Coagulation
$C$. Emulsification $c$. Colloidal solution preparation
$D$. Electrophoresis $d$. Purification of colloidal solution

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