Among the following compounds,the one that ca | vedclass

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(C) The dehydration of alcohols proceeds via the formation of a carbocation intermediate. The ease of dehydration depends on the stability of the carb

Vedclass · Accepted Answer

$CH_3-CH_2-C(CH_3)(OH)-CH_2-CH_3$

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(C) The dehydration of alcohols proceeds via the formation of a carbocation intermediate. The ease of dehydration depends on the stability of the carbocation formed,which follows the order: $3^\circ > 2^\circ > 1^\circ$. $(A)$ $CH_3-CH_2-CH_2-CH_2-CH_2-OH$ is a primary $(1^\circ)$ alcohol. $(B)$ $CH_3-CH_2-CH_2-CH(OH)-CH_3$ is a secondary $(2^\circ)$ alcohol. $(C)$ $CH_3-CH_2-C(CH_3)(OH)-CH_2-CH_3$ is a tertiary $(3^\circ)$ alcohol. $(D)$ $CH_3-CH_2-CH(CH_3)-CH_2-CH_2-OH$ is a primary $(1^\circ)$ alcohol. Since option $(C)$ is a tertiary alcohol,it forms the most stable carbocation and thus dehydrates most easily.

Among the following compounds,the one that can be dehydrated most easily is:

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