Among the following compounds I-IV,which one | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction sequence involves nucleophilic substitution followed by precipitation with silver ions. Compound $IV$ contains a benzylic iodide grou

Vedclass · Accepted Answer

$IV$

Vedclass · Answer

(B) The reaction sequence involves nucleophilic substitution followed by precipitation with silver ions. Compound $IV$ contains a benzylic iodide group $(-CH_{2}I)$. When treated with $NaOH$,the iodide ion $(I^{-})$ is displaced via an $S_{N}2$ mechanism to form an alcohol. The resulting $I^{-}$ ions react with $AgNO_{3}$ in the presence of $HNO_{3}$ to form a yellow precipitate of silver iodide $(AgI)$. Compounds $I$,$II$,and $III$ contain aryl halides where the halogen is directly attached to the benzene ring,making them resistant to nucleophilic substitution under these conditions.

Among the following compounds $I-IV$,which one forms a yellow precipitate on reacting sequentially with $(i)$ $NaOH$,$(ii)$ dil. $HNO_{3}$,and $(iii)$ $AgNO_{3}$?

Similar Questions

Which of the following reactions is used for the conversion of alkyl chloride to alkyl iodide?

Write a note on $S_{N}2$ mechanism.

The ${S_{N}2}$ reaction of an asymmetric carbon compound always gives:

The correct pair$(s)$ of the ambident nucleophiles is (are):
$(A)$ $AgCN / KCN$
$(B)$ $RCOOAg / RCOOK$
$(C)$ $AgNO_{2} / KNO_{2}$
$(D)$ $AgI / KI$

Benzene $\xrightarrow[{Anhy. AlCl_3}]{{CH_3Cl}} A \,$ $\xrightarrow[{hv}]{{Cl_2 (1 \, mole)}} B$ $\xrightarrow{{AgCN}} C$
Which is correct for the above reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module