Aluminium reacts with $NaOH$ and forms compound '$X$'. If the coordination number of aluminium in '$X$' is $6$,the correct formula of $X$ is:
- A$[Al(H_2O)_4(OH)_2]^+$
- B$[Al(H_2O)_3(OH)_3]$
- C$[Al(H_2O)_2(OH)_4]^-$
- D$[Al(H_2O)_6](OH)_3$
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$A$ few grams of borax is dissolved in distilled water. The $pH$ range of the resultant solution is
Explain the following:
$(1)$ Aluminum forms $[AlF_6]^{3-}$ ion but boron does not form $[BF_6]^{3-}$ ion.
$(2)$ $PbX_2$ is more stable than $PbX_4$.
$(1)$ Aluminum forms $[AlF_6]^{3-}$ ion but boron does not form $[BF_6]^{3-}$ ion.
$(2)$ $PbX_2$ is more stable than $PbX_4$.
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