Alkanes can be prepared by the electrolysis o | vedclass

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Question

(A) The reaction at the anode is: $2 CH_3COO^- \rightarrow C_2H_6(g) + 2 CO_2(g) + 2 e^-$. The reaction at the cathode is: $2 H_2O + 2 e^- \rightarrow

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(A) The reaction at the anode is: $2 CH_3COO^- ightarrow C_2H_6(g) + 2 CO_2(g) + 2 e^-$. The reaction at the cathode is: $2 H_2O + 2 e^- ightarrow H_2(g) + 2 OH^-$. Total charge passed: $Q = I 	imes t = 20 \ A 	imes 9650 \ s = 193000 \ C$. Number of moles of electrons: $n_{e^-} = \frac{193000}{96500} = 2 \ mol$. From the stoichiometry: $2 \ mol$ of $e^-$ produce $1 \ mol$ of $C_2H_6$,$2 \ mol$ of $CO_2$,and $1 \ mol$ of $H_2$. Mass of gases: $Mass(C_2H_6) = 1 \ mol 	imes 30 \ g/mol = 30 \ g$. $Mass(CO_2) = 2 \ mol 	imes 44 \ g/mol = 88 \ g$. $Mass(H_2) = 1 \ mol 	imes 2 \ g/mol = 2 \ g$. Total mass = $30 + 88 + 2 = 120 \ g$.

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