Alkaline oxidative fusion of MnO_2 gives A wh | vedclass

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(B) The alkaline oxidative fusion of $MnO_2$ with $KOH$ in the presence of air (or $KNO_3$) produces potassium manganate $(K_2MnO_4)$,where the mangan

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$MnO_4^{2-}$ and $MnO_4^{-}$

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(B) The alkaline oxidative fusion of $MnO_2$ with $KOH$ in the presence of air (or $KNO_3$) produces potassium manganate $(K_2MnO_4)$,where the manganate ion is $MnO_4^{2-}$. Thus,$A = MnO_4^{2-}$.$2MnO_2 + 4KOH + O_2 \rightarrow 2K_2MnO_4 + 2H_2O$Electrolytic oxidation of the green manganate solution $(MnO_4^{2-})$ in an alkaline medium converts it into purple permanganate $(MnO_4^{-})$. Thus,$B = MnO_4^{-}$.$2MnO_4^{2-} + H_2O + [O] \rightarrow 2MnO_4^{-} + 2OH^{-}$Therefore,$A$ and $B$ are $MnO_4^{2-}$ and $MnO_4^{-}$ respectively.

Alkaline oxidative fusion of $MnO_2$ gives $A$ which on electrolytic oxidation in alkaline solution produces $B$. $A$ and $B$ respectively are:

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