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(D) Intramolecular aldol condensation involves the formation of a ring within a single molecule containing two carbonyl groups. $(1)$ Cyclodecane$-1,6

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Vedclass · Answer

(D) Intramolecular aldol condensation involves the formation of a ring within a single molecule containing two carbonyl groups. $(1)$ Cyclodecane$-1,6-$dione undergoes intramolecular aldol condensation to form a bicyclic $\alpha, \beta-$unsaturated ketone. $(2)$ $6-$Oxoheptanal undergoes intramolecular aldol condensation to form cyclohex$-2-$en$-1-$one. $(3)$ $2-$Acetylbenzaldehyde undergoes intramolecular aldol condensation to form inden$-1-$one. $(4)$ The reaction between $1-$tetralone and formaldehyde is an intermolecular aldol condensation (specifically a Claisen-Schmidt condensation),not an intramolecular one. Therefore,the product shown in option $D$ is not formed via intramolecular aldol condensation.

Aldol condensation is a popular and classical method to prepare $\alpha, \beta-$unsaturated carbonyl compounds. This reaction can be both intermolecular and intramolecular. Predict which one of the following is not a product of intramolecular aldol condensation?

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