Albumin has a gold number of 0.09. What is th | vedclass

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(B) The gold number is defined as the minimum amount of protective colloid in $mg$ required to prevent the coagulation of $10 \ mL$ of a gold sol when

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$0.36$

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(B) The gold number is defined as the minimum amount of protective colloid in $mg$ required to prevent the coagulation of $10 \ mL$ of a gold sol when $1 \ mL$ of $10 \% \ NaCl$ solution is added. Given: Gold number of albumin = $0.09 \ mg$. This means $0.09 \ mg$ of albumin protects $10 \ mL$ of gold sol from $1 \ mL$ of $10 \% \ NaCl$. We need to protect $40 \ mL$ of gold sol from $4 \ mL$ of $10 \% \ NaCl$. Since the amount of gold sol is $4$ times the standard volume $(40 \ mL / 10 \ mL = 4)$,the amount of albumin required will be $4 	imes 0.09 \ mg = 0.36 \ mg$.

Albumin has a gold number of $0.09$. What is the minimum amount of albumin (in $mg$) required to protect the coagulation of $40 \ mL$ of gold sol from $4 \ mL$ of $10 \% \ NaCl$ solution?

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