After the emission of an $\alpha$-particle from the atom $_{92}X^{238}$,the number of neutrons in the resulting atom will be:

$A$ radium $_{88}Ra^{224}$ isotope,on emission of an $\alpha$-particle,gives rise to a new element whose mass number and atomic number will be:

Identify $[A]$ and $[B]$ in the following reaction sequence:
${ }_{89}^{227} Ac$ $\xrightarrow{-\beta} [A]$ $\xrightarrow{-\alpha} [B]$ $\xrightarrow{-\alpha} { }_{86}^{219} Rn$

The atomic number of a radioactive element increases by one unit in:

The disintegration of an isotope of sodium,$_{11}Na^{24} \to _{12}Mg^{24} + _{-1}e^0$,shown is due to

$_{72}^{180}X$ $\xrightarrow{2\alpha}$ $\xrightarrow{\beta}$ $\xrightarrow{\gamma} _{Z}^{A}X'$. The values of $Z$ and $A$ are: