Adiabatic free expansion of an ideal gas must | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the first law of thermodynamics,$Q = \Delta U + W$. In an adiabatic process,$Q = 0$. In free expansion,the external pressure $P_{ext}

Vedclass · Accepted Answer

Isothermal

Vedclass · Answer

(C) According to the first law of thermodynamics,$Q = \Delta U + W$. In an adiabatic process,$Q = 0$. In free expansion,the external pressure $P_{ext} = 0$,so the work done $W = P_{ext} \Delta V = 0$. Substituting these values into the first law: $0 = \Delta U + 0$,which implies $\Delta U = 0$. For an ideal gas,internal energy $U$ is a function of temperature only $(U = f(T))$. Since $\Delta U = 0$,the change in temperature $\Delta T = 0$,meaning the temperature remains constant. Therefore,the process is isothermal.

Adiabatic free expansion of an ideal gas must be

Similar Questions

If $\Delta H$ is the change in enthalpy,$\Delta U$ is the change in internal energy,$N_P$ is the number of moles of products,and $N_r$ is the number of moles of reactants,then which of the following is correct for a gaseous reaction?

$A$ sample of $1.0 \ mol$ of a monoatomic ideal gas is taken through a cyclic process of expansion and compression as shown in the figure. What will be the value of $\Delta H$ for the cycle as a whole?

At a definite temperature,for which of the following reactions will the value of $(\Delta E - \Delta H)$ be maximum?

Identify the type of system if boiling water is kept in a half-filled closed vessel.

Which among the following properties is $NOT$ a state function?

Vedclass Test Series

Exam Paper Generator

Online Exam Module