Addition of a mineral acid to an olefin bond | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction follows the electrophilic addition mechanism,where the rate-determining step is the formation of a carbocation intermediate. In the g

Vedclass · Accepted Answer

Vedclass · Answer

(C) The reaction follows the electrophilic addition mechanism,where the rate-determining step is the formation of a carbocation intermediate. In the given molecule,there are two double bonds: one in the ring and one in the side chain. The double bond in the side chain is more substituted and its protonation leads to a more stable $3^o$ carbocation compared to the secondary carbocation that would form from the ring double bond. Therefore,the $H^+$ ion adds to the terminal carbon of the side chain to form a $3^o$ carbocation,which is then attacked by the $Br^-$ ion to form the major product.

Addition of a mineral acid to an olefin bond leads to a major product. Identify it.

Similar Questions

The decreasing order of the rate of reaction of the following molecules towards electrophilic addition reaction is:

How many cyclic structures are possible for $C_4H_6$?

Identify $A$ in the following reaction sequence:

Write chemical equations for the combustion reaction of the following hydrocarbons:
$(i)$ Butane $(ii)$ Pentene $(iii)$ Hexyne $(iv)$ Toluene

Give the reaction for the following transformations:
$1$. Ethanol from ethane
$2$. Benzene from $2-$hexene

Vedclass Test Series

Exam Paper Generator

Online Exam Module