Action of hydrogen chloride on $CH_3-C(CH_3)=CH_2$ and on $CH \equiv CH$ will predominantly give the compounds,respectively

  • A
    $CH_3-C(CH_3)=CHCl$ and $ClCH_2-CH_2Cl$
  • B
    $CH_3-CCl(CH_3)-CH_3$ and $CH_3-CHCl_2$
  • C
    $CH_3-C(CH_3)=CHCl$ and $CH_3-CHCl_2$
  • D
    $CH_3-C(CH_3)=CH_2$ and $ClCH_2-CH_2Cl$

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