Acetone and acetaldehyde are differentiated by

The product $(A)$ of the reaction is:

The semicarbazone of cyclobutanone is represented as:

Number of molecules from the following which cannot give the iodoform reaction is $:$ Ethanol,Isopropyl alcohol,Bromoacetone,$2-$Butanol,$2-$Butanone,Butanal,$2-$Pentanone,$3-$Pentanone,Pentanal,and $3-$Pentanol.

Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$ : $Image-I$ can be easily reduced using $Zn-Hg / HCl$ to $Image-II$.
Reason $R : Zn-Hg / HCl$ is used to reduce carbonyl group to $-CH_2-$ group.
In the light of the above statements,choose the correct answer from the options given below:

$Ph-CH(OH)-CH_3$ $\xrightarrow{PCC} A$ $\xrightarrow[(ii) H^{+}/\Delta]{(i) NH_2OH} B + C$
In the given reaction sequence,$B$ and $C$ are: