According to the nuclear reaction _4Be + _2He | vedclass

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(B) In a nuclear reaction,both the total atomic number and the total mass number must be conserved on both sides of the equation.Let the mass number o

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(B) In a nuclear reaction,both the total atomic number and the total mass number must be conserved on both sides of the equation.Let the mass number of $Be$ be $A$.The reaction is $_4Be^A + _2He^4 	o _6C^{12} + _0n^1$.Equating the mass numbers on both sides:$A + 4 = 12 + 1$$A + 4 = 13$$A = 13 - 4 = 9$.Therefore,the mass number of the $Be$ atom is $9$.

According to the nuclear reaction $_4Be + _2He^4 \to _6C^{12} + _0n^1$,what is the mass number of the $Be$ atom?

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