According to Moseley's law,the frequency of a | vedclass

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(B) Moseley's law states that the frequency $
u$ of a characteristic $X$-ray spectral line is given by the relation: $\sqrt{
u} = a(Z - b)$.Here,$Z$

Vedclass · Accepted Answer

Square of the atomic number of the element

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(B) Moseley's law states that the frequency $
u$ of a characteristic $X$-ray spectral line is given by the relation: $\sqrt{
u} = a(Z - b)$.Here,$Z$ is the atomic number of the element,and $a$ and $b$ are constants that depend on the specific type of spectral line (e.g.,$K$,$L$,etc.).Squaring both sides of the equation,we get: $
u = a^2(Z - b)^2$.Since $b$ is a screening constant and is typically small compared to $Z$ for high-$Z$ elements,the frequency $
u$ is directly proportional to the square of the atomic number $(Z^2)$.Therefore,the frequency varies as the square of the atomic number of the element.

According to Moseley's law,the frequency of a spectral line in the $X$-ray spectrum varies as:

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