The acceleration-time graph is given. If the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The change in velocity $\Delta v$ is equal to the area under the acceleration-time $(a-t)$ graph.The area of the triangle in the $(a-t)$ graph is

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(B) The change in velocity $\Delta v$ is equal to the area under the acceleration-time $(a-t)$ graph.The area of the triangle in the $(a-t)$ graph is given by:$	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$$	ext{Area} = \frac{1}{2} 	imes 2\,s 	imes 10\,m/s^2 = 10\,m/s$We know that $\Delta v = v_f - v_i$,where $v_f$ is the final velocity and $v_i$ is the initial velocity.$v_f - 5\,m/s = 10\,m/s$$v_f = 15\,m/s$Thus,the velocity after $2\,s$ is $15\,m/s$.

The acceleration-time graph is given. If the initial velocity is $5\,m/s$,then the velocity after $2\,s$ is.......$m/s$.

Similar Questions

What is acceleration? What is its direction,and state its $SI$ unit.

$A$ body in one-dimensional motion has zero speed at an instant. At that instant,it must have:

At any instant,the velocity and acceleration of a particle moving along a straight line are $v$ and $a$. The speed of the particle is increasing if

If the speed of a moving object decreases,what are the directions of its velocity and acceleration?

The velocity of a body depends on time according to the equation $v = \frac{t^2}{10} + 20$. The body is undergoing

Vedclass Test Series

Exam Paper Generator

Online Exam Module