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(B) Given: Length of wire $l = 2 \, m$, Current $I = 1 \, A$.When the wire is bent into a circle, the circumference of the circle equals the length of

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$1 / \pi \, A \cdot m^2$

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(B) Given: Length of wire $l = 2 \, m$, Current $I = 1 \, A$.When the wire is bent into a circle, the circumference of the circle equals the length of the wire: $2 \pi r = l$.Substituting the value of $l$: $2 \pi r = 2 \implies r = 1 / \pi \, m$.The area of the circular coil is $A = \pi r^2 = \pi (1 / \pi)^2 = 1 / \pi \, m^2$.The magnetic moment $M$ is given by $M = I 	imes A$.Substituting the values: $M = 1 	imes (1 / \pi) = 1 / \pi \, A \cdot m^2$.

$A$ wire of length $2 \, m$ carrying a current of $1 \, A$ is bent to form a circle. The magnetic moment of the coil is

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