A wire has a resistance of 6 ,Omega. It is cu | vedclass

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Question

(B) Given the initial resistance of the wire is $R = 6 \,\Omega$.When the wire is cut into two equal parts,the resistance of each part becomes $R' = R

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(B) Given the initial resistance of the wire is $R = 6 \,\Omega$.When the wire is cut into two equal parts,the resistance of each part becomes $R' = R/2 = 6/2 = 3 \,\Omega$.When these two equal resistors are connected in parallel,the equivalent resistance $R_{eq}$ is given by the formula:$\frac{1}{R_{eq}} = \frac{1}{R'} + \frac{1}{R'} = \frac{2}{R'}$$R_{eq} = \frac{R'}{2} = \frac{3}{2} = 1.5 \,\Omega$.Alternatively,using the shortcut formula for two equal resistors in parallel: $R_{eq} = \frac{R}{4} = \frac{6}{4} = 1.5 \,\Omega$.

$A$ wire has a resistance of $6 \,\Omega$. It is cut into two equal parts and both parts are connected in parallel. The new resistance is ................ $\Omega$.

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