A wire can be broken by applying a load of 20 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Breaking stress is a material property and remains constant for a given material.Breaking stress $= \frac{F}{A} = 	ext{constant}$.Let $F_1 = 20\,

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(C) Breaking stress is a material property and remains constant for a given material.Breaking stress $= \frac{F}{A} = 	ext{constant}$.Let $F_1 = 20\,kg\,wt$ be the force for a wire of radius $r_1$ and area $A_1 = \pi r_1^2$.Let $F_2$ be the force for a wire of radius $r_2 = 2r_1$ and area $A_2 = \pi r_2^2 = \pi (2r_1)^2 = 4\pi r_1^2$.Since the breaking stress is constant,$\frac{F_1}{A_1} = \frac{F_2}{A_2}$.$F_2 = F_1 	imes \frac{A_2}{A_1} = 20 	imes \frac{4\pi r_1^2}{\pi r_1^2} = 20 	imes 4 = 80\,kg\,wt$.

$A$ wire can be broken by applying a load of $20\,kg$ weight. The force required to break the wire of twice the diameter is ......... $kg\,wt$.

Similar Questions

Archaea that live in hot springs belong to which group?

Which of the following plants are used as green manure in crop fields and in sandy soils?

If the equation $12x^2 + 7xy - py^2 - 18x + qy + 6 = 0$ represents a pair of perpendicular straight lines,then

The two enantiomers of secondary butyl chloride differ from each other in which one of the following properties?

Which of the following is a fossil pteridophyte?

Vedclass Test Series

Exam Paper Generator

Online Exam Module