A weight can be hung in any of the following | vedclass

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Question

Consider the string makes an angle $	heta$ with the horizontal, Taking $FBD$ of the block, we get $m g=2 T \sin 	heta$

$	herefore T=\frac{m g}{2

Vedclass · Accepted Answer

$C$

Vedclass · Answer

Consider the string makes an angle $	heta$ with the horizontal, Taking $FBD$ of the block, we get $m g=2 T \sin 	heta$

$	herefore T=\frac{m g}{2 \sin 	heta}$

Now, as the denominator decreases Tension becomes more and the string breaks. It means $	heta$ should be minimum in case of maximum Tension and to break the string.

Thus, $\mathrm{C}$ is the case

A weight can be hung in any of the following four ways by string of same type. In which case is the string most likely to break?

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