A vessel contains 1 mole of O_2 gas (molar ma | vedclass

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(C) The ideal gas equation is given by $PV = \mu RT$,where $P$ is pressure,$V$ is volume,$\mu$ is the number of moles,$R$ is the universal gas constan

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$2P$

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(C) The ideal gas equation is given by $PV = \mu RT$,where $P$ is pressure,$V$ is volume,$\mu$ is the number of moles,$R$ is the universal gas constant,and $T$ is the temperature.Since the vessels are identical,the volume $V$ is constant. $R$ is also a constant.Therefore,$P \propto \mu T$.For the first vessel (containing $O_2$): $P_1 = P$,$\mu_1 = 1$,$T_1 = T$.For the second vessel (containing $He$): $P_2 = ?$,$\mu_2 = 1$,$T_2 = 2T$.Taking the ratio: $\frac{P_2}{P_1} = \frac{\mu_2 T_2}{\mu_1 T_1}$.Substituting the values: $\frac{P_2}{P} = \frac{1 	imes 2T}{1 	imes T} = 2$.Thus,$P_2 = 2P$.

$A$ vessel contains $1$ mole of $O_2$ gas (molar mass $32$) at a temperature $T$. The pressure of the gas is $P$. An identical vessel containing $1$ mole of $He$ gas (molar mass $4$) at temperature $2T$ has a pressure of:

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