A vertical pole of length 6, m casts a shadow | vedclass

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Question

(C) Let $AB$ be the height of the tower and $CD$ be the height of the pole.Let $BE$ be the shadow of the tower and $DF$ be the shadow of the pole.Sinc

Vedclass · Accepted Answer

$42$

Vedclass · Answer

(C) Let $AB$ be the height of the tower and $CD$ be the height of the pole.Let $BE$ be the shadow of the tower and $DF$ be the shadow of the pole.Since the sun's rays fall at the same angle at the same time,the triangles formed by the objects and their shadows are similar.Therefore,$	riangle ABE \sim 	riangle CDF$ by $AA$ similarity criterion.This implies that the ratios of their corresponding sides are equal:$\frac{AB}{CD} = \frac{BE}{DF}$Given $CD = 6\, m$,$DF = 4\, m$,and $BE = 28\, m$.Substituting the values:$\frac{AB}{6} = \frac{28}{4}$$\frac{AB}{6} = 7$$AB = 7 	imes 6 = 42\, m$.Thus,the height of the tower is $42\, m$.

$A$ vertical pole of length $6\, m$ casts a shadow $4\, m$ long on the ground and at the same time a tower casts a shadow $28\, m$ long. Find the height of the tower. (in $m$)

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$A$ vertical pole of length $6\, m$ casts a shadow $4\, m$ long on the ground and at the same time a tower casts a shadow $28\, m$ long. Find the height of the tower. (in $m$)

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State which pairs of triangles in the figure are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form.

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