$A$ tuning fork $A$ produces $4$ beats/sec with another tuning fork $B$ of frequency $320 \text{ Hz}$. On filing the fork $A$,$4$ beats/sec are again heard. The frequency of fork $A$ after filing is .... $\text{Hz}$

Ten tuning forks are arranged in increasing order of frequency in such a way that any two nearest tuning forks produce $4 \text{ beats/sec}$. The highest frequency is twice the lowest. The possible highest and lowest frequencies are:

Each of the two strings of length $51.6 \, cm$ and $49.1 \, cm$ are tensioned separately by $20 \, N$ force. The mass per unit length of both strings is the same and equal to $1 \, g/m$. When both strings vibrate simultaneously,the number of beats is:

Two identical piano wires,kept under the same tension $T$,have a fundamental frequency of $600\, Hz$. The fractional increase in the tension of one of the wires which will lead to the occurrence of $6\, beats/s$ when both the wires oscillate together would be:

Two tuning forks $A$ and $B$ vibrating simultaneously produce $5$ beats. The frequency of $B$ is $512 \ Hz$. It is observed that if one arm of $A$ is filed,the number of beats increases. The frequency of $A$ is: (in $Hz$)

The frequency of a tuning fork is $256 \, Hz$. The velocity of sound in air is $344 \, ms^{-1}$. The distance travelled (in $meters$) by the sound during the time in which the tuning fork completes $32$ vibrations is