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(B) The given truth table is:$A=0, B=0 \implies Y=1$$A=1, B=0 \implies Y=0$$A=0, B=1 \implies Y=0$$A=1, B=1 \implies Y=0$For a $NOR$ gate,the output i

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$NOR$ gate

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(B) The given truth table is:$A=0, B=0 \implies Y=1$$A=1, B=0 \implies Y=0$$A=0, B=1 \implies Y=0$$A=1, B=1 \implies Y=0$For a $NOR$ gate,the output is defined by the Boolean expression $Y = \overline{A + B}$.Calculating for each case:$1$. For $A=0, B=0$: $Y = \overline{0+0} = \overline{0} = 1$.$2$. For $A=1, B=0$: $Y = \overline{1+0} = \overline{1} = 0$.$3$. For $A=0, B=1$: $Y = \overline{0+1} = \overline{1} = 0$.$4$. For $A=1, B=1$: $Y = \overline{1+1} = \overline{1} = 0$.This matches the given truth table. Therefore,the correct option is $B$.

$A$ truth table is given below. Which of the following logic gates corresponds to this truth table?
$A: 0, 1, 0, 1$
$B: 0, 0, 1, 1$
$Y: 1, 0, 0, 0$

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$A$ truth table is given below. Which of the following logic gates corresponds to this truth table?$A: 0, 1, 0, 1$$B: 0, 0, 1, 1$$Y: 1, 0, 0, 0$