A truck starting from rest moves with an acce | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The acceleration of the truck is $a_t = 5 \ m/s^2$. The maximum acceleration the block can have due to friction is $a_{max} = \mu g = 0.2 	imes 1

Vedclass · Accepted Answer

Vedclass · Answer

(B) The acceleration of the truck is $a_t = 5 \ m/s^2$. The maximum acceleration the block can have due to friction is $a_{max} = \mu g = 0.2 	imes 10 = 2 \ m/s^2$.Since the truck accelerates at $5 \ m/s^2$,the block will slip on the truck and move with a constant acceleration of $a_{max} = 2 \ m/s^2$ relative to the ground.For the first $1 \ s$,the velocity of the block with respect to the ground is $v = u + at = 0 + 2 	imes 1 = 2 \ m/s$.After $1 \ s$,the truck moves with a constant velocity,so the acceleration of the truck becomes $0$. The friction force also becomes $0$,and the block continues to move with the velocity it attained at $t = 1 \ s$,which is $2 \ m/s$.Thus,the velocity of the block increases linearly to $2 \ m/s$ in $1 \ s$ and then remains constant at $2 \ m/s$.

Similar Questions

$A$ spring-block system is placed on a rough horizontal floor. The block is pulled towards the right to give the spring an elongation $x_0$ such that $\frac{\mu mg}{K} < x_0 < \frac{2\mu mg}{K}$,and then released. Which of the following statements is correct?

Which is a suitable method to decrease friction?

Imagine the situation in which the given arrangement is placed inside a trolley that can move only in the horizontal direction,as shown in the figure. If the trolley is accelerated horizontally along the positive $x$-axis with $a_0$,then choose the correct statement$(s)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module