A transverse sinusoidal wave of amplitude a, | vedclass

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(D) The maximum particle velocity of a transverse wave is given by $v_{\max} = a\omega = a(2\pi n).$Given $v_{\max} = v/10,$ where $v = 10 \ m/s,$ we

Vedclass · Accepted Answer

Both $(A)$ and $(C)$

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(D) The maximum particle velocity of a transverse wave is given by $v_{\max} = a\omega = a(2\pi n).$Given $v_{\max} = v/10,$ where $v = 10 \ m/s,$ we have $v_{\max} = 10/10 = 1 \ m/s.$Substituting $a = 10^{-3} \ m,$ we get $10^{-3} 	imes 2\pi n = 1 \implies n = \frac{10^3}{2\pi} \ Hz.$Using the wave speed relation $v = n\lambda,$ we find $\lambda = \frac{v}{n} = \frac{10}{10^3 / 2\pi} = 2\pi 	imes 10^{-2} \ m.$Thus,both options $(A)$ and $(C)$ are correct.

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