A transmitting antenna has a height of 320, m | vedclass

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(A) The maximum distance $d$ for line-of-sight communication is given by the formula: $d = \sqrt{2Rh_T} + \sqrt{2Rh_R}$.Here,$R$ is the radius of the

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$224$

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(A) The maximum distance $d$ for line-of-sight communication is given by the formula: $d = \sqrt{2Rh_T} + \sqrt{2Rh_R}$.Here,$R$ is the radius of the Earth $\approx 6400\, km = 6.4 	imes 10^6\, m$.$h_T = 320\, m$ and $h_R = 2000\, m$.Substituting the values:$d = \sqrt{2 	imes 6.4 	imes 10^6 	imes 320} + \sqrt{2 	imes 6.4 	imes 10^6 	imes 2000}$$d = \sqrt{4096 	imes 10^6} + \sqrt{25600 	imes 10^6}$$d = 64000 + 160000 = 224000\, m$.Converting to kilometers: $d = 224\, km$.

$A$ transmitting antenna has a height of $320\, m$ and that of the receiving antenna is $2000\, m$. The maximum distance between them for satisfactory communication in line-of-sight mode is $d$. The value of $d$ is $\ldots \ldots \, km$.

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