A train is travelling at a speed of 90, km, h | vedclass

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(A) Given:Initial velocity $u = 90\, km\, h^{-1} = 90 	imes \frac{5}{18} = 25\, m\, s^{-1}$.Final velocity $v = 0\, m\, s^{-1}$ (since the train come

Vedclass · Accepted Answer

$625$

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(A) Given:Initial velocity $u = 90\, km\, h^{-1} = 90 	imes \frac{5}{18} = 25\, m\, s^{-1}$.Final velocity $v = 0\, m\, s^{-1}$ (since the train comes to rest).Acceleration $a = -0.5\, m\, s^{-2}$ (negative sign indicates retardation).We need to find the distance $S$.Using the third equation of motion: $v^{2} - u^{2} = 2aS$.Substituting the values: $0^{2} - (25)^{2} = 2 	imes (-0.5) 	imes S$.$-625 = -1 	imes S$.$S = 625\, m$.Therefore,the train will travel $625\, m$ before coming to rest.

$A$ train is travelling at a speed of $90\, km\, h^{-1}$. Brakes are applied so as to produce a uniform acceleration of $-0.5\, m\, s^{-2}$. Find how far the train will go before it is brought to rest. (in $, m$)

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