A time varying current $i$ is passed through a resistance $R$ as shown in figure. The total heat generated in the resistance is
$11i_0^2R{t_0}$
$13i_0^2R{t_0}$
$17i_0^2R{t_0}$
$15i_0^2R{t_0}$
In a building there are $15$ bulbs of $45\; \mathrm{W}, 15$ bulbs of $100\; \mathrm{W}, 15$ small fans of $10 \;\mathrm{W}$ and $2$ heaters of $1 \;\mathrm{kW}$. The voltage of electric main is $220\; \mathrm{V}$. The minimum fuse capacity (rated value) of the building will be: .......... $A$
The mechanism of the heat produced in a conductor when an electric current flows through it, can be explained on the basis of
Power dissipated across the $8 \,\,\Omega$ resistor in the circuit shown here is $2\,\, watt.$ The power dissipated in watt units across the $3 \,\,\Omega$ resistor is
A light bulb of resistance $R=16 \,\Omega$ is attached in series with an infinite resistor network with identical resistances $r$ as shown below. A $10 \,V$ battery drives current in the circuit. ............. $\Omega$ the value of $r$ such that the bulb dissipates about $1 \,W$ of power.
In India electricity is supplied for domestic use at $220 \,V$. It is supplied at $110 \,V$ in USA. If the resistance of a $60 \,W$ bulb for use in India is $R$, the resistance of a $60 \,W$ bulb for use in USA will be