A thin metal disc of radius r floats on the w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the disc to be in equilibrium,the total downward force (weight of the disc) must be equal to the total upward force.The total upward force con

Vedclass · Accepted Answer

$2\pi rT \cos 	heta + W$

Vedclass · Answer

(C) For the disc to be in equilibrium,the total downward force (weight of the disc) must be equal to the total upward force.The total upward force consists of:$1$. The upthrust (buoyant force) acting on the disc,which is equal to the weight of the displaced water,$W$.$2$. The vertical component of the surface tension force acting along the perimeter of the disc.The surface tension force $F_s$ acts along the perimeter $2\pi r$ at an angle $	heta$ with the vertical. The vertical component of this force is $F_{s,v} = T 	imes (2\pi r) 	imes \cos 	heta$.Therefore,the weight of the metal disc $Mg = W + 2\pi rT \cos 	heta$.

$A$ thin metal disc of radius $r$ floats on the water surface and bends the surface downwards along the perimeter,making an angle $\theta$ with the vertical edge of the disc. If the disc displaces a weight of water $W$ and the surface tension of water is $T$,then the weight of the metal disc is:

Similar Questions

Explain why is hot soup more tasty than the colder one?

The maximum force,in addition to the weight,required to pull a wire of $5.0 \, cm$ long from the surface of water at a temperature of $20^\circ C$ is $728 \, dynes$. The surface tension of water is:

The value of surface tension of a liquid at critical temperature is

If a drop of liquid breaks into smaller droplets,it results in the lowering of the temperature of the droplets. Let a drop of radius $R$ break into $N$ small droplets,each of radius $r$. Estimate the drop in temperature.

Vedclass Test Series

Exam Paper Generator

Online Exam Module