$A$ thin disc of radius $b = 2a$ has a concentric hole of radius $a$ in it (see figure). It carries uniform surface charge $\sigma$. If the electric field on its axis at height $h$ $(h << a)$ from its centre is given as $Ch$,then the value of $C$ is:

  • A
    $\frac{\sigma}{4a\epsilon_0}$
  • B
    $\frac{\sigma}{8a\epsilon_0}$
  • C
    $\frac{\sigma}{a\epsilon_0}$
  • D
    $\frac{\sigma}{2a\epsilon_0}$

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