A thief is spotted by a policeman from a dist | vedclass

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Question

(A) The initial distance between the policeman and the thief is $200 	ext{ meters} = 0.2 	ext{ km}$.The relative speed of the policeman with respect

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(A) The initial distance between the policeman and the thief is $200 	ext{ meters} = 0.2 	ext{ km}$.The relative speed of the policeman with respect to the thief is $12 	ext{ km/h} - 10 	ext{ km/h} = 2 	ext{ km/h}$.The time taken by the policeman to catch the thief is given by the formula: $	ext{Time} = \frac{	ext{Distance}}{	ext{Relative Speed}}$.$	ext{Time} = \frac{0.2 	ext{ km}}{2 	ext{ km/h}} = 0.1 	ext{ hours} = \frac{1}{10} 	ext{ hours}$.The distance the thief has run before being caught is calculated as: $	ext{Distance} = 	ext{Speed of thief} 	imes 	ext{Time}$.$	ext{Distance} = 10 	ext{ km/h} 	imes 0.1 	ext{ h} = 1 	ext{ km}$.

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